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lecture_23
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| Both sides previous revisionPrevious revisionNext revision | Previous revision | ||
| lecture_23 [2017/04/25 09:18] – rupert | lecture_23 [2017/05/06 09:59] (current) – rupert | ||
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| ===== The distance from a point to a line ===== | ===== The distance from a point to a line ===== | ||
| - | ==== Dot product method ==== | + | ==== Cross product method ==== |
| Suppose $L$ is a line in $\def\rt{\mathbb{R}^3}\def\rn{\mathbb{R}^n}\rt$. Let $A$ be a point on $L$ and let $\def\vv{\vec v}\vv$ be a direction vector along $L$. | Suppose $L$ is a line in $\def\rt{\mathbb{R}^3}\def\rn{\mathbb{R}^n}\rt$. Let $A$ be a point on $L$ and let $\def\vv{\vec v}\vv$ be a direction vector along $L$. | ||
| Line 22: | Line 22: | ||
| \[ \def\dist{\text{dist}}\dist(B, | \[ \def\dist{\text{dist}}\dist(B, | ||
| - | ==== Cross product method ==== | + | ==== Dot product method ==== |
| The method above relies on the cross product, so only works in $\def\c# | The method above relies on the cross product, so only works in $\def\c# | ||
| Line 41: | Line 41: | ||
| \[ \dist(B, | \[ \dist(B, | ||
| - | ===== The distance between | + | ===== The distance between lines in $\mathbb{R}^3$ ===== |
| + | |||
| + | ==== Skew lines ==== | ||
| Suppose that $L_1$ and $L_2$ are skew lines in $\rt$: lines which are not parallel and do not cross. | Suppose that $L_1$ and $L_2$ are skew lines in $\rt$: lines which are not parallel and do not cross. | ||
| Line 90: | Line 92: | ||
| The formula $\dist(L_1, | The formula $\dist(L_1, | ||
| - | * skew lines (not parallel, not intersecting) | + | * skew lines (not parallel, not intersecting), as we saw above, |
| - | * actually: any non-parallel lines $L_1$, $L_2$ | + | * and actually: any non-parallel lines $L_1$, $L_2$. We can see this by noticing that if the lines above intersect, then $L_1$ lies in $\Pi$, so the formula gives $\dist(L_1, |
| What about parallel lines? | What about parallel lines? | ||
| * The formula can't work because we'd have $\vec v_1=\vec v_2$ so $\vec n=\vec v_1\times \vec v_2=\vec 0$ | * The formula can't work because we'd have $\vec v_1=\vec v_2$ so $\vec n=\vec v_1\times \vec v_2=\vec 0$ | ||
lecture_23.1493111914.txt.gz · Last modified: by rupert
