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lecture_17_slides

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lecture_17_slides [2017/04/03 15:29] – [Exercise] rupertlecture_17_slides [2017/04/03 15:34] (current) – [Corollary] rupert
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 ==== Example ==== ==== Example ====
  
-  * Let $\vec v=\m{1\\2}$ and $\vec w=\m{-2\\1}$ +What's the angle between $\vec v=\m{1\\2}$ and $\vec w=\m{-2\\1}$? 
-  * Then $\dp vw=1(-2)+2(1)=-2+2=0$. +  * $\dp vw=1(-2)+2(1)=-2+2=0$. 
-  * On the other hand, $\|\vec v\|=\sqrt5=\|\vec w\|$+  * $\|\vec v\|=\sqrt5=\|\vec w\|$
   * So the angle $\theta$ between $\vec v$ and $\vec w$ has $ 0=\dp vw=\sqrt 5\times \sqrt 5 \times \cos\theta$   * So the angle $\theta$ between $\vec v$ and $\vec w$ has $ 0=\dp vw=\sqrt 5\times \sqrt 5 \times \cos\theta$
   * So $5\cos\theta=0$, so $\cos\theta=0$,   * So $5\cos\theta=0$, so $\cos\theta=0$,
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   * So $\vv\cdot\ww=\|\vv\|\,\|\ww\|\cos\theta$. ■    * So $\vv\cdot\ww=\|\vv\|\,\|\ww\|\cos\theta$. ■ 
  
-==== Corollary ====+==== Corollary ====
  
 If $\vv$ and $\ww$ are non-zero vectors and $\theta$ is the angle between them, then $\cos\theta=\displaystyle\frac{\vv\cdot\ww}{\|\vv\|\,\|\ww\|}$. If $\vv$ and $\ww$ are non-zero vectors and $\theta$ is the angle between them, then $\cos\theta=\displaystyle\frac{\vv\cdot\ww}{\|\vv\|\,\|\ww\|}$.
  
-==== Corollary ====+==== Corollary ====
 If $\vv$ and $\ww$ are non-zero vectors with $\vv\cdot\ww=0$, then $\vv$ and $\ww$ are **orthogonal**: they are at right-angles. If $\vv$ and $\ww$ are non-zero vectors with $\vv\cdot\ww=0$, then $\vv$ and $\ww$ are **orthogonal**: they are at right-angles.
  
lecture_17_slides.1491233341.txt.gz · Last modified: by rupert

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